If a solution containing 58.085g of mercury (II) acetate is allowed to react completely with a solution containing 15.488 g of sodium dichromate, how…

If a solution containing 58.085g of mercury (II) acetate is allowed to react completely with a solution containing 15.488 g of sodium dichromate, how many grams of solid precipitate will be formed.
………….g
How many grams of the reactant in excess will remain after the reaction?

0 replies

Leave a Reply

Want to join the discussion?
Feel free to contribute!

Leave a Reply